Integrand size = 38, antiderivative size = 134 \[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=\frac {(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac {(A (3-2 m)-B (5+2 m)) \cos (e+f x) \operatorname {Hypergeometric2F1}\left (2,\frac {1}{2}+m,\frac {3}{2}+m,\frac {1}{2} (1+\sin (e+f x))\right ) (a+a \sin (e+f x))^m}{16 c^2 f (1+2 m) \sqrt {c-c \sin (e+f x)}} \]
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Time = 0.23 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {3051, 2824, 2746, 70} \[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=\frac {(A (3-2 m)-B (2 m+5)) \cos (e+f x) (a \sin (e+f x)+a)^m \operatorname {Hypergeometric2F1}\left (2,m+\frac {1}{2},m+\frac {3}{2},\frac {1}{2} (\sin (e+f x)+1)\right )}{16 c^2 f (2 m+1) \sqrt {c-c \sin (e+f x)}}+\frac {(A+B) \cos (e+f x) (a \sin (e+f x)+a)^m}{4 f (c-c \sin (e+f x))^{5/2}} \]
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Rule 70
Rule 2746
Rule 2824
Rule 3051
Rubi steps \begin{align*} \text {integral}& = \frac {(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac {\left (B c \left (-\frac {5}{2}-m\right )-A c \left (-\frac {3}{2}+m\right )\right ) \int \frac {(a+a \sin (e+f x))^m}{(c-c \sin (e+f x))^{3/2}} \, dx}{4 c^2} \\ & = \frac {(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac {\left (\left (B c \left (-\frac {5}{2}-m\right )-A c \left (-\frac {3}{2}+m\right )\right ) \cos (e+f x)\right ) \int \sec ^3(e+f x) (a+a \sin (e+f x))^{\frac {3}{2}+m} \, dx}{4 a c^3 \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}} \\ & = \frac {(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac {\left (a^2 \left (B c \left (-\frac {5}{2}-m\right )-A c \left (-\frac {3}{2}+m\right )\right ) \cos (e+f x)\right ) \text {Subst}\left (\int \frac {(a+x)^{-\frac {1}{2}+m}}{(a-x)^2} \, dx,x,a \sin (e+f x)\right )}{4 c^3 f \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}} \\ & = \frac {(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac {(A (3-2 m)-B (5+2 m)) \cos (e+f x) \operatorname {Hypergeometric2F1}\left (2,\frac {1}{2}+m,\frac {3}{2}+m,\frac {1}{2} (1+\sin (e+f x))\right ) (a+a \sin (e+f x))^m}{16 c^2 f (1+2 m) \sqrt {c-c \sin (e+f x)}} \\ \end{align*}
Time = 33.23 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.19 \[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=-\frac {\cos (e+f x) \left (B (5+2 m) \operatorname {Hypergeometric2F1}\left (2,\frac {1}{2}+m,\frac {3}{2}+m,\frac {1}{2} (1+\sin (e+f x))\right ) \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^4-4 \left (B+2 B m+A \operatorname {Hypergeometric2F1}\left (3,\frac {1}{2}+m,\frac {3}{2}+m,\frac {1}{2} (1+\sin (e+f x))\right ) (-1+\sin (e+f x))^2\right )\right ) (a (1+\sin (e+f x)))^m}{16 c^2 (f+2 f m) (-1+\sin (e+f x))^2 \sqrt {c-c \sin (e+f x)}} \]
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\[\int \frac {\left (a +a \sin \left (f x +e \right )\right )^{m} \left (A +B \sin \left (f x +e \right )\right )}{\left (c -c \sin \left (f x +e \right )\right )^{\frac {5}{2}}}d x\]
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\[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=\int { \frac {{\left (B \sin \left (f x + e\right ) + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m}}{{\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=\int { \frac {{\left (B \sin \left (f x + e\right ) + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m}}{{\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac {5}{2}}} \,d x } \]
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Exception generated. \[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx=\int \frac {\left (A+B\,\sin \left (e+f\,x\right )\right )\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m}{{\left (c-c\,\sin \left (e+f\,x\right )\right )}^{5/2}} \,d x \]
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